8/18/2023 0 Comments Bode plot multisim decade![]() ![]() Remembering that the product of terms in the transfer function will be seen as the sum of terms in the logarithmic domain, we will see how to sketch the individual terms separately and then add them graphically to obtain the final result. The curve of the absolute value of a first order term s has a 20 dB/decade slope crossing the horizontal axis at w = 1. The phase of this term is 90 ° at any frequency. ![]() The curve of K* s also has a 20 dB/decade slope but it crosses the axis at w = 1/K i.e., where the absolute value of the product ½ K* s ½ = 1. Similarly, the absolute value of the term K/ s has a -20 dB/decade slope the phase is -90 ° at any frequency but it crosses the w axis at w = K, where the absolute value of the fraction The next first order term (in the second example), s -1 = 1/s, is similar: its absolute value has a -20 dB/decade slope its phase is -90 ° at any frequency and it crosses the w -axis at w = 1. The next first order term to sketch is 1+sT. The amplitude plot is a horizontal line until w 1 = 1/T, after which it slopes upward at 20 dB/decade. The phase equals zero at small frequencies, 90 ° at high frequencies and 45 ° at w 1 = 1/T. A good approximation for phase is that it is zero until 0.1* w 1 = 0.1/T and is nearly 90 ° above 10* w 1 = 10/T.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |